82=16t^2

Solution for 82=16t^2 equation:

82=16t^2

We move all terms to the left:

82-(16t^2)=0

a = -16; b = 0; c = +82;
Δ = b2-4ac
Δ = 02-4·(-16)·82
Δ = 5248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5248}=\sqrt{64*82}=\sqrt{64}*\sqrt{82}=8\sqrt{82}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{82}}{2*-16}=\frac{0-8\sqrt{82}}{-32}
=-\frac{8\sqrt{82}}{-32}
=-\frac{\sqrt{82}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{82}}{2*-16}=\frac{0+8\sqrt{82}}{-32}
=\frac{8\sqrt{82}}{-32}
=\frac{\sqrt{82}}{-4}
$